2017 AMC 12A Problem 10

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10.

Chloé chooses a real number uniformly at random from the interval [0,2017].[0,2017]. Independently, Laurent chooses a real number uniformly at random from the interval [0,4034].[0,4034]. What is the probability that Laurent's number is greater than Chloé's number?

12\dfrac{1}{2}

23\dfrac{2}{3}

34\dfrac{3}{4}

56\dfrac{5}{6}

78\dfrac{7}{8}

Answer: C
Concepts:geometric probabilitysymmetrycomplementary probability
Difficulty rating: 1560
Solution:

With probability 12,\dfrac{1}{2}, Laurent's number lies in [2017,4034],[2017,4034], which exceeds any number Chloé could choose, so he wins for certain.

With the other probability 12,\dfrac{1}{2}, Laurent's number lies in [0,2017],[0,2017], matching Chloé's interval; by symmetry he is larger half the time. The total probability is 121+1212=34. \dfrac{1}{2}\cdot1+\dfrac{1}{2}\cdot\dfrac{1}{2}=\dfrac{3}{4}.

Thus, the correct answer is C.

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