2016 AMC 12A Problem 4

Attempt Problem 4 of the 2016 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2016 AMC 12A solutions, or check the answer key.

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4.

The mean, median, and mode of the 77 data values 60,100,x,40,50,200,9060, 100, x, 40, 50, 200, 90 are all equal to x.x. What is the value of x?x?

5050

6060

7575

9090

100100

Answer: D
Concepts:meanmedian (data)mode
Difficulty rating: 1100
Solution:

The mean condition gives 60+100+x+40+50+200+907=540+x7=x, \begin{gathered} \small \dfrac{60+100+x+40+50+200+90}{7}\\ =\dfrac{540+x}{7}\\ =x, \end{gathered} so 540+x=7x540+x=7x and x=90.x=90.

In nondecreasing order the data are 40,50,60,90,90,100,200,40, 50, 60, 90, 90, 100, 200, so the median is 9090 and the mode is 90,90, as required.

Thus, the correct answer is D.

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