2016 AMC 12A Problem 10

Attempt Problem 10 of the 2016 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2016 AMC 12A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

10.

Five friends sat in a movie theater in a row containing 55 seats, numbered 11 to 55 from left to right. (The directions “left” and “right” are from the point of view of the people as they sit in the seats.) During the movie Ada went to the lobby to get some popcorn. When she returned, she found that Bea had moved two seats to the right, Ceci had moved one seat to the left, and Dee and Edie had switched seats, leaving an end seat for Ada. In which seat had Ada been sitting before she got up?
11
22
33
44
55
Answer: B
Concepts:invariantlogical deduction
Small hint:
The total rightward movement must equal the total leftward movement
Big hint:
Bea moves +2,+2, Ceci moves −1,-1, and Dee and Edie cancel; find Ada’s shift
Solution:
The net displacement of all five friends is zero. Dee and Edie swapped seats, so their movements cancel. Bea moved +2+2 and Ceci moved −1,-1, a net of +1,+1, so Ada must move −1-1 to balance.
Ada returns to an end seat; since she moved one seat to the left, that seat must be seat 1,1, so she had been sitting in seat 2.2.
Thus, the correct answer is B.
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