2014 AMC 12A Problem 9

Attempt Problem 9 of the 2014 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2014 AMC 12A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

9.

Five positive consecutive integers starting with aa have average b.b. What is the average of 55 consecutive integers that start with b?b?
a+3a+3
a+4a+4
a+5a+5
a+6a+6
a+7a+7
Answer: B
Concepts:meanarithmetic sequence
Small hint:
The average of consecutive integers is the middle one
Big hint:
From the first set b=a+2b=a+2, and the new average is b+2b+2
Solution:
The integers a,a+1,a+2,a+3,a+4a,a+1,a+2,a+3,a+4 have average a+2,a+2, so b=a+2.b=a+2.
The integers starting at bb have average b+2=(a+2)+2=a+4.b+2=(a+2)+2=a+4.
Thus, the correct answer is B.
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