2013 AMC 12B Problem 4

Attempt Problem 4 of the 2013 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2013 AMC 12B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

4.

Ray’s car averages 4040 miles per gallon of gasoline, and Tom’s car averages 1010 miles per gallon of gasoline. Ray and Tom each drive the same number of miles. What is the cars’ combined rate of miles per gallon of gasoline?
1010
1616
2525
3030
4040
Answer: B
Concepts:rateratio and proportion
Small hint:
Combined mileage is total miles divided by total gallons, not the average of the two rates
Big hint:
If each drives DD miles, the gallons used are D40\dfrac{D}{40} and D10\dfrac{D}{10}
Solution:
If each drives DD miles, together they cover 2D2D miles using D40+D10=D8\dfrac{D}{40}+\dfrac{D}{10} = \dfrac{D}{8} gallons. The combined rate is 2DD8=16\dfrac{2D}{\frac{D}{8}} = 16 miles per gallon. Thus, the correct answer is B.
LIVE by Po-Shen Loh
Programs

LIVE Classes

Self-Paced Classes

Stars

Scholarship

About Us

Who Is Po-Shen Loh?

Email Contact

Newsletter

Jobs

Become a Star

For a more Thought Full world.

© 2026 Expii, Inc.