2010 AMC 12A Problem 21

Attempt Problem 21 of the 2010 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2010 AMC 12A solutions, or check the answer key.

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21.

The graph of y=x6−10x5y=x^6-10x^5 +29x4−4x3+ax2+29x^4-4x^3+ax^2 lies above the line y=bx+cy=bx+c except at three values of x,x, where the graph and the line intersect. What is the largest of those values?
44
55
66
77
88
Answer: A
Concepts:polynomialfactoringcompleting the square
Small hint:
The graph minus the line is nonnegative with three double roots, so it equals ((x−p)(x−q)(x−r))2\big((x-p)(x-q)(x-r)\big)^2
Big hint:
Match the coefficients of x5,x4,x3x^5,x^4,x^3 to determine the cubic, then factor it
Solution:
Let f(x)f(x) be the graph minus the line. It is nonnegative and vanishes at three points, each a double root, so f(x)=(x3−Ax2+Bx−C)2.f(x)=\big(x^3-Ax^2+Bx-C\big)^2.
Matching coefficients gives −2A=−10⇒A=5,-2A=-10\Rightarrow A=5, then A2+2B=29⇒B=2,A^2+2B=29\Rightarrow B=2, then −2C−2AB=−4⇒C=−8.-2C-2AB=-4\Rightarrow C=-8.
Thus the cubic is x3−5x2+2x+8x^3-5x^2+2x+8 =(x+1)(x−2)(x−4),=(x+1)(x-2)(x-4), with roots −1,2,-1,2, and 4.4. The largest is 4.4.
Thus, A is the correct answer.
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