2018 AMC 12A Problem 21

Below is the professionally curated solution for Problem 21 of the 2018 AMC 12A, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2018 AMC 12A solutions, or check the answer key.

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Concepts:polynomialinequalitybounding to limit cases

Difficulty rating: 2210

21.

Which of the following polynomials has the greatest real root?

x19+2018x11+1x^{19} + 2018x^{11} + 1

x17+2018x11+1x^{17} + 2018x^{11} + 1

x19+2018x13+1x^{19} + 2018x^{13} + 1

x17+2018x13+1x^{17} + 2018x^{13} + 1

2019x+20182019x + 2018

Solution:

Each polynomial in choices A–D has no positive root and exactly one negative root, which lies in (1,0)(-1, 0) (it is positive at 00 and negative at 1-1) and is increasing there. On the interval (1,0),(-1, 0), x19<x17x^{19} \lt x^{17} and x13<x11.x^{13} \lt x^{11}. Increasing a term makes the polynomial larger, which pushes its root to the left (smaller). So the smallest exponents give the greatest root, favoring choice B (x17+2018x11+1x^{17} + 2018x^{11} + 1) over A, C, and D.

The linear choice E has root 20182019=(112019),-\tfrac{2018}{2019} = -\left(1 - \tfrac{1}{2019}\right), very close to 1;-1; evaluating the polynomial of choice B there gives a negative value, so B's root lies to the right of E's. Hence B has the greatest real root.

Thus, the correct answer is B.

Problem 21 in Other Years