2017 AMC 12B Problem 21

Below is the professionally curated solution for Problem 21 of the 2017 AMC 12B, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2017 AMC 12B solutions, or check the answer key.

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Concepts:divisibilitymeanbounding to limit cases

Difficulty rating: 2040

21.

Last year Isabella took 77 math tests and received 77 different scores, each an integer between 9191 and 100,100, inclusive. After each test she noticed that the average of her test scores was an integer. Her score on the seventh test was 95.95. What was her score on the sixth test?

9292

9494

9696

9898

100100

Solution:

Let SS be the sum of all seven scores. Then SS is a multiple of 77 with 658S679,658 \le S \le 679, so S{658,665,672,679}.S \in \{658, 665, 672, 679\}. Since the average after six tests is an integer, S95S - 95 is a multiple of 6,6, which forces S=665.S = 665. Then the first six scores sum to 570,570, a multiple of 5;5; the average after five tests is an integer, so the first five scores also sum to a multiple of 5,5, making the sixth score a multiple of 5.5. Since all scores differ and the seventh is 95,95, the sixth must be 100.100.

Thus, the correct answer is E.

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