2008 AMC 12B Problem 6

Attempt Problem 6 of the 2008 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2008 AMC 12B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

6.

Postman Pete has a pedometer to count his steps. The pedometer records up to 9999999999 steps, then flips over to 0000000000 on the next step. Pete plans to determine his mileage for a year. On January 11 Pete sets the pedometer to 00000.00000. During the year, the pedometer flips from 9999999999 to 0000000000 forty-four times. On December 3131 the pedometer reads 50000.50000. Pete takes 18001800 steps per mile. Which of the following is closest to the number of miles Pete walked during the year?
25002500
30003000
35003500
40004000
45004500
Answer: A
Concepts:place valueestimationunit conversion
Small hint:
Each flip of the pedometer represents 100000100000 steps; add the final reading of 5000050000
Big hint:
Divide the total number of steps by 18001800 to convert to miles
Solution:
Each flip counts 100000100000 steps, so the year’s steps total 44⋅100000+50000=4,450,000. \begin{aligned} &44 \cdot 100000 \\ &\quad {}+ 50000 = 4{,}450{,}000. \end{aligned}
At 18001800 steps per mile, the mileage is 4,450,0001800≈2472,\dfrac{4{,}450{,}000}{1800} \approx 2472, which is closest to 2500.2500.
Thus, the correct answer is A.
LIVE by Po-Shen Loh
Programs

LIVE Classes

Self-Paced Classes

Stars

Scholarship

About Us

Who Is Po-Shen Loh?

Email Contact

Newsletter

Jobs

Become a Star

For a more Thought Full world.

© 2026 Expii, Inc.