2008 AMC 12B Problem 15

Attempt Problem 15 of the 2008 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2008 AMC 12B solutions, or check the answer key.

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15.

On each side of a unit square, an equilateral triangle of side length 11 is constructed. On each new side of each equilateral triangle, another equilateral triangle of side length 11 is constructed. The interiors of the square and the 1212 triangles have no points in common. Let RR be the region formed by the union of the square and all the triangles, and let SS be the smallest convex polygon that contains R.R. What is the area of the region that is inside SS but outside R?R?

14\dfrac{1}{4}

24\dfrac{\sqrt{2}}{4}

11

3\sqrt{3}

232\sqrt{3}

Answer: C
Concepts:triangle areaangle chasingtrigonometry
Difficulty rating: 1660
Solution:

The convex hull SS differs from RR only near the four corners of the square, where a small triangular gap forms. Each gap triangle has two sides of length 11 (outer edges of adjacent triangles).

The angle between those two sides is 36090460=30,360^\circ - 90^\circ - 4 \cdot 60^\circ = 30^\circ, so each gap has area 1211sin30=14. \tfrac12 \cdot 1 \cdot 1 \cdot \sin 30^\circ = \tfrac14.

The total area is 414=1.4 \cdot \tfrac14 = 1.

Thus, the correct answer is C.

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