2008 AMC 12B Problem 10

Attempt Problem 10 of the 2008 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2008 AMC 12B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

10.

Bricklayer Brenda would take 99 hours to build a chimney alone, and bricklayer Brandon would take 1010 hours to build it alone. When they work together, they talk a lot, and their combined output is decreased by 1010 bricks per hour. Working together, they build the chimney in 55 hours. How many bricks are in the chimney?
500500
900900
950950
10001000
19001900
Answer: B
Concepts:ratelinear equation
Small hint:
If the chimney has nn bricks, Brenda lays n9\tfrac{n}{9} per hour and Brandon lays n10\tfrac{n}{10} per hour
Big hint:
Together they lay n9+n10−10\tfrac{n}{9} + \tfrac{n}{10} - 10 bricks per hour, and 55 hours of this equals nn
Solution:
Let nn be the number of bricks. Alone, Brenda lays n9\tfrac{n}{9} bricks per hour and Brandon lays n10.\tfrac{n}{10}. Together, their rate is n9+n10−10.\tfrac{n}{9} + \tfrac{n}{10} - 10.
Working for 55 hours completes the chimney: 5(n9+n10−10)=n. 5\left(\tfrac{n}{9} + \tfrac{n}{10} - 10\right) = n. Expanding, 5n9+5n10−50=n,\tfrac{5n}{9} + \tfrac{5n}{10} - 50 = n, so 95n90−n=50,\tfrac{95n}{90} - n = 50, giving 5n90=50.\tfrac{5n}{90} = 50.
Hence n=900.n = 900.
Thus, the correct answer is B.
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