2008 AMC 12A Problem 18

Attempt Problem 18 of the 2008 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2008 AMC 12A solutions, or check the answer key.

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18.

Triangle ABC,ABC, with sides of length 5,6,5, 6, and 7,7, has one vertex on the positive xx-axis, one on the positive yy-axis, and one on the positive zz-axis. Let OO be the origin. What is the volume of tetrahedron OABC?OABC?

85\sqrt{85}

90\sqrt{90}

95\sqrt{95}

1010

105\sqrt{105}

Answer: C
Concepts:3D geometrysystem of equationsvolume
Difficulty rating: 1910
Solution:

Let A=(a,0,0),A = (a, 0, 0), B=(0,b,0),B = (0, b, 0), C=(0,0,c).C = (0, 0, c). Assigning the sides, a2+b2=25,b2+c2=36,a2+c2=49. \begin{aligned} a^2 + b^2 &= 25, \\ b^2 + c^2 &= 36, \\ a^2 + c^2 &= 49. \end{aligned}

Adding gives a2+b2+c2=55,a^2 + b^2 + c^2 = 55, so a2=19,a^2 = 19, b2=6,b^2 = 6, and c2=30.c^2 = 30.

The volume is 16abc=1619630=163420=95. \begin{aligned} \dfrac{1}{6}abc &= \dfrac{1}{6}\sqrt{19 \cdot 6 \cdot 30} \\ &= \dfrac{1}{6}\sqrt{3420} \\ &= \sqrt{95}. \end{aligned}

Thus, C is the correct answer.

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