2022 AMC 12A Problem 18

Attempt Problem 18 of the 2022 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2022 AMC 12A solutions, or check the answer key.

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18.

Let TkT_k be the transformation of the coordinate plane that first rotates the plane kk degrees counterclockwise around the origin and then reflects the plane across the yy-axis. What is the least positive integer nn such that performing the sequence of transformations T1,T_1, T2,T_2, T3,T_3, ,\ldots, TnT_n returns the point (1,0)(1,0) back to itself?

359359

360360

719719

720720

721721

Answer: A
Concepts:transformationcasework
Difficulty rating: 2010
Small Hint:

A point at angle θ\theta is sent by TkT_k to angle (180k)θ(180-k)-\theta

Big Hint:

Track the angle of (1,0);(1,0); also consider odd n,n, where the net map is a reflection

Solution:

Rotating a point at angle θ\theta by kk^\circ gives θ+k,\theta+k, and reflecting across the yy-axis sends angle ϕ\phi to 180ϕ.180-\phi. So TkT_k sends θ\theta to (180k)θ.(180-k)-\theta.

Starting from (1,0)(1,0) at angle 0,0, applying T1,T2,T_1,T_2,\ldots gives angles 179,1,178,2,177,.179,-1,178,-2,177,\ldots. After an even number 2m2m of steps the angle is m,-m, and after an odd number 2m+12m+1 it is 179m.179-m.

For the point to return, the angle must be a multiple of 360.360^\circ. The even case needs m=360,m=360, i.e. n=720.n=720. The odd case needs 179m=0,179-m=0, i.e. m=179m=179 and n=359,n=359, where the net reflection fixes (1,0).(1,0).

The least such nn is 359.359.

Thus, the correct answer is A.

Problem 17#17
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