2022 AMC 12A Problem 18

Below is the professionally curated solution for Problem 18 of the 2022 AMC 12A, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2022 AMC 12A solutions, or check the answer key.

All of the real AMC 8, AMC 10, AMC 12, and AIME problems in our complete solution collection are used with official legal permission of the Mathematical Association of America (MAA).

Concepts:transformationcasework

Difficulty rating: 2010

18.

Let TkT_k be the transformation of the coordinate plane that first rotates the plane kk degrees counterclockwise around the origin and then reflects the plane across the yy-axis. What is the least positive integer nn such that performing the sequence of transformations T1,T2,T3,,TnT_1,T_2,T_3,\ldots,T_n returns the point (1,0)(1,0) back to itself?

359359

360360

719719

720720

721721

Solution:

Rotating a point at angle θ\theta by kk^\circ gives θ+k,\theta+k, and reflecting across the yy-axis sends angle ϕ\phi to 180ϕ.180-\phi. So TkT_k sends θ\theta to (180k)θ.(180-k)-\theta.

Starting from (1,0)(1,0) at angle 0,0, applying T1,T2,T_1,T_2,\ldots gives angles 179,1,178,2,177,.179,-1,178,-2,177,\ldots. After an even number 2m2m of steps the angle is m,-m, and after an odd number 2m+12m+1 it is 179m.179-m.

For the point to return, the angle must be a multiple of 360.360^\circ. The even case needs m=360,m=360, i.e. n=720.n=720. The odd case needs 179m=0,179-m=0, i.e. m=179m=179 and n=359,n=359, where the net reflection fixes (1,0).(1,0).

The least such nn is 359.359.

Thus, the correct answer is A.

Problem 18 in Other Years