2009 AMC 12B Problem 18

Below is the professionally curated solution for Problem 18 of the 2009 AMC 12B, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2009 AMC 12B solutions, or check the answer key.

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Concepts:geometric probabilitydistance rate and time

Difficulty rating: 1930

18.

Rachel and Robert run on a circular track. Rachel runs counterclockwise and completes a lap every 9090 seconds, and Robert runs clockwise and completes a lap every 8080 seconds. Both start from the start line at the same time. At some random time between 1010 minutes and 1111 minutes after they begin to run, a photographer standing inside the track takes a picture that shows one-fourth of the track, centered on the starting line. What is the probability that both Rachel and Robert are in the picture?

116\dfrac{1}{16}

18\dfrac{1}{8}

316\dfrac{3}{16}

14\dfrac{1}{4}

516\dfrac{5}{16}

Solution:

The picture covers the arc within 18\dfrac{1}{8} lap of the start on each side. At 600600 s Rachel has run 6236\tfrac{2}{3} laps, 3030 s short of the line; a quarter lap takes her 22.522.5 s, so she is in view between 3011.25=18.7530 - 11.25 = 18.75 s and 30+11.25=41.2530 + 11.25 = 41.25 s of the 1010th minute.

At 600600 s Robert is 4040 s from the line; a quarter lap takes 2020 s, so he is in view between 3030 and 5050 s. Both appear between 3030 and 41.2541.25 s, a window of 11.2511.25 s out of 60,60, giving probability 11.2560=316.\dfrac{11.25}{60} = \dfrac{3}{16}.

Thus, the correct answer is C.

Problem 18 in Other Years