2006 AMC 12B Problem 18

Attempt Problem 18 of the 2006 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2006 AMC 12B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

18.

An object in the plane moves from one lattice point to another. At each step, the object may move one unit to the right, one unit to the left, one unit up, or one unit down. If the object starts at the origin and takes a ten-step path, how many different points could be the final point?
120120
121121
221221
230230
231231
Answer: B
Concepts:lattice pointparitybasic counting
Small hint:
After 1010 steps the endpoint (a,b)(a, b) satisfies ∣a∣+∣b∣≤10|a| + |b| \le 10 with a+ba + b even
Big hint:
Count lattice points with even coordinate sum inside the diamond ∣a∣+∣b∣≤10|a| + |b| \le 10
Solution:
Each step changes the coordinate sum by 1,1, so after 1010 steps the endpoint (a,b)(a, b) has a+ba + b even, and ∣a∣+∣b∣≤10.|a| + |b| \le 10. Any such point is reachable: walk ∣a∣+∣b∣|a| + |b| steps to it, then use the remaining even number of steps going out and back.
The reachable points lie on the lines a+b=2ka + b = 2k for −5≤k≤5.-5 \le k \le 5. Each such line meets the diamond in exactly 1111 lattice points.
With 1111 lines and 1111 points each, there are 121121 points.
Thus, the correct answer is B.
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