2005 AMC 12B Problem 9

Attempt Problem 9 of the 2005 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2005 AMC 12B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

9.

On a certain math exam, 10%10\% of the students got 7070 points, 25%25\% got 8080 points, 20%20\% got 8585 points, 15%15\% got 9090 points, and the rest got 9595 points. What is the difference between the mean and the median score on this exam?
00
11
22
44
55
Answer: B
Concepts:meanmedian (data)
Small hint:
The remaining percentage scored 9595: 100−10−25−20−15100 - 10 - 25 - 20 - 15
Big hint:
For the median, find where the cumulative percentage passes 50%50\%
Solution:
The percentage scoring 9595 is 100−10−25−20−15=30.100 - 10 - 25 - 20 - 15 = 30.
The mean is 0.10(70)+0.25(80)+0.20(85)+0.15(90)+0.30(95)=86. \begin{aligned} &0.10(70) + 0.25(80) \\ &\quad {}+ 0.20(85) + 0.15(90) \\ &\quad {}+ 0.30(95) = 86. \end{aligned}
Cumulatively, 10%10\% are below 80,80, 35%35\% are at or below 80,80, and 55%55\% are at or below 85.85. The middle scores fall at 85,85, so the median is 85.85.
The difference is 86−85=1.86 - 85 = 1.
Thus, the correct answer is B.
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