2003 AMC 12B Problem 21

Attempt Problem 21 of the 2003 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2003 AMC 12B solutions, or check the answer key.

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21.

An object moves 88 cm in a straight line from AA to B,B, turns at an angle α,\alpha, measured in radians and chosen at random from the interval (0,π),(0, \pi), and moves 55 cm in a straight line to C.C. What is the probability that AC<7?AC \lt 7?

16\dfrac{1}{6}

15\dfrac{1}{5}

14\dfrac{1}{4}

13\dfrac{1}{3}

12\dfrac{1}{2}

Answer: D
Concepts:law of cosinesgeometric probabilitytrigonometry
Difficulty rating: 1910
Solution:

Let β=πα\beta = \pi - \alpha be the interior angle of ABC\triangle ABC at B.B. By the Law of Cosines, AC2=82+522(8)(5)cosβ=8980cosβ. \begin{aligned} &AC^2 = 8^2 + 5^2 \\ &\quad {}- 2(8)(5)\cos\beta \\ &= 89 - 80\cos\beta. \end{aligned}

Then AC<7AC \lt 7 means 8980cosβ<49,89 - 80\cos\beta \lt 49, i.e. cosβ>12,\cos\beta \gt \dfrac{1}{2}, i.e. β<π3.\beta \lt \dfrac{\pi}{3}.

As α\alpha is uniform on (0,π),(0, \pi), so is β.\beta. The probability is π/3π=13. \frac{\pi/3}{\pi} = \frac{1}{3}.

Thus, the correct answer is D.

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