2003 AMC 12B Problem 20

Attempt Problem 20 of the 2003 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2003 AMC 12B solutions, or check the answer key.

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20.

Part of the graph of f(x)=ax3+bx2+cx+df(x) = ax^3 + bx^2 + cx + d is shown. What is b?b?
−4-4
−2-2
00
22
44
Answer: B
Concepts:polynomialsubstitution
Small hint:
Read off f(−1)=0,f(-1) = 0, f(1)=0,f(1) = 0, and f(0)=2f(0) = 2 from the graph
Big hint:
Adding f(1)+f(−1)f(1) + f(-1) eliminates aa and c,c, leaving 2b+2d=02b + 2d = 0
Solution:
The graph passes through (−1,0),(-1, 0), (1,0),(1, 0), and (0,2).(0, 2). So f(0)=d=2.f(0) = d = 2.
Adding f(1)+f(−1)=(a+b+c+d)+(−a+b−c+d)=2b+2d=0, \begin{aligned} &f(1) + f(-1) \\ &= (a + b + c + d) \\ &\quad {}+ (-a + b - c + d) \\ &= 2b + 2d = 0, \end{aligned} so b=−d=−2.b = -d = -2.
Thus, the correct answer is B.
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