2003 AMC 12A Problem 21

Attempt Problem 21 of the 2003 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2003 AMC 12A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

21.

The graph of the polynomial P(x)=x5+ax4+bx3+cx2+dx+e \begin{aligned} &P(x) = x^5 + ax^4 + bx^3 \\ &\quad {}+ cx^2 + dx + e \end{aligned}
has five distinct xx-intercepts, one of which is at (0,0).(0, 0). Which of the following coefficients cannot be zero?
aa
bb
cc
dd
ee
Answer: D
Concepts:Vieta’s Formulaspolynomial
Small hint:
P(0)=0P(0)=0 forces e=0e=0
Big hint:
Factor out x;x; the constant term of the remaining quartic is the product of the four nonzero roots
Solution:
Since (0,0)(0,0) is an intercept, P(0)=e=0,P(0)=e=0, so P(x)P(x) =x(x4+ax3+bx2+cx+d).=x\left(x^4+ax^3+bx^2+cx+d\right).
The four remaining intercepts are nonzero and distinct, and dd equals their product, which is therefore nonzero.
Any of a,b,ca,b,c can be zero for suitable choices of those roots, but d≠0.d\neq0.
Thus, the correct answer is D.
LIVE by Po-Shen Loh
Programs

LIVE Classes

Self-Paced Classes

Stars

Scholarship

About Us

Who Is Po-Shen Loh?

Email Contact

Newsletter

Jobs

Become a Star

For a more Thought Full world.

© 2026 Expii, Inc.