2002 AMC 12A Problem 4

Attempt Problem 4 of the 2002 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2002 AMC 12A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

4.

Find the degree measure of an angle whose complement is 25%25\% of its supplement.
4848
6060
7575
120120
150150
Answer: B
Concepts:angle sumlinear equation
Small hint:
The complement is 90−x90 - x and the supplement is 180−x180 - x
Big hint:
Solve 90−x=14(180−x)90 - x = \dfrac14(180 - x)
Solution:
Let the angle be x.x. Then 90−x=14(180−x),90 - x = \dfrac14(180 - x), so 360−4x=180−x.360 - 4x = 180 - x.
This gives 3x=180,3x = 180, so x=60.x = 60.
Thus, the correct answer is B.
LIVE by Po-Shen Loh
Programs

LIVE Classes

Self-Paced Classes

Stars

Scholarship

About Us

Who Is Po-Shen Loh?

Email Contact

Newsletter

Jobs

Become a Star

For a more Thought Full world.

© 2026 Expii, Inc.