2001 AMC 12 Problem 9

Attempt Problem 9 of the 2001 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2001 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

9.

Let ff be a function satisfying f(xy)=f(x)yf(xy) = \dfrac{f(x)}{y} for all positive real numbers xx and y.y. If f(500)=3,f(500) = 3, what is the value of f(600)?f(600)?
11
22
52\dfrac{5}{2}
33
185\dfrac{18}{5}
Answer: C
Concepts:functional equationsubstitution
Small hint:
Write 600600 as 500500 times a convenient factor
Big hint:
f(600)=f ⁣(500⋅65)=f(500)65f(600) = f\!\left(500 \cdot \dfrac{6}{5}\right) = \dfrac{f(500)}{\frac{6}{5}}
Solution:
Choose x=500x = 500 and y=65y = \dfrac{6}{5} so that xy=600.xy = 600. Then f(600)=f(500)65=365=52. f(600) = \dfrac{f(500)}{\frac{6}{5}} = \dfrac{3}{\frac{6}{5}} = \dfrac{5}{2}.
Thus, the correct answer is C.
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