2001 AMC 12 Problem 20

Attempt Problem 20 of the 2001 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2001 AMC 12 solutions, or check the answer key.

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20.

Points A=(3,9),A = (3, 9), B=(1,1),B = (1, 1), C=(5,3),C = (5, 3), and D=(a,b)D = (a, b) lie in the first quadrant and are the vertices of quadrilateral ABCD.ABCD. The quadrilateral formed by joining the midpoints of AB,\overline{AB}, BC,\overline{BC}, CD,\overline{CD}, and DA\overline{DA} is a square. What is the sum of the coordinates of point D?D?

77

99

1010

1212

1616

Answer: C
Concepts:coordinate geometrymidpointvector
Difficulty rating: 1880
Solution:

The midpoints are M=(2,5)M = (2, 5) of AB\overline{AB} and N=(3,2)N = (3, 2) of BC.\overline{BC}.

For the midpoint quadrilateral to be a square, consecutive sides are perpendicular and equal. With NM=1,3,\overrightarrow{NM} = \langle -1, 3 \rangle, the side MQ\overrightarrow{MQ} to the midpoint QQ of DA\overline{DA} must be 3,1,\langle 3, 1 \rangle, so Q=(5,6).Q = (5, 6).

Since QQ is the midpoint of DA\overline{DA} and A=(3,9),A = (3, 9), we get D=2QA=(7,3).D = 2Q - A = (7, 3). The sum of its coordinates is 7+3=10.7 + 3 = 10.

Thus, the correct answer is C.

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