1998 AMC 12 Problem 20

Attempt Problem 20 of the 1998 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1998 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

20.

Three cards, each with a positive integer written on it, are lying face-down on a table. Casey, Stacy, and Tracy are told that
(a) the numbers are all different,
(b) they sum to 13,13, and
(c) they are in increasing order, left to right.
First, Casey looks at the number on the leftmost card and says, “I don’t have enough information to determine the other two numbers.” Then Tracy looks at the number on the rightmost card and says, “I don’t have enough information to determine the other two numbers.” Finally, Stacy looks at the number on the middle card and says, “I don’t have enough information to determine the other two numbers.” Assume that each person knows that the other two reason perfectly and hears their comments. What number is on the middle card?
22
33
44
55
There is not enough information to determine the number.
Answer: C
Concepts:logicordered triples
Small hint:
List all increasing positive triples with sum 1313
Big hint:
Eliminate triples in the order of the three statements, using what each speaker has learned
Solution:
The eight triples are (1,2,10),(1,3,9),(1,4,8),(1,5,7),(2,3,8),(2,4,7),(2,5,6),(3,4,6). \begin{gathered} (1,2,10),(1,3,9),\\ (1,4,8),(1,5,7),\\ (2,3,8),(2,4,7),\\ (2,5,6),(3,4,6). \end{gathered} Casey’s statement excludes (3,4,6).(3,4,6). With that known, Tracy’s statement excludes rightmost values 10,9,10,9, and 6.6. The remaining triples are (1,4,8),(2,3,8)(1,4,8),(2,3,8) and (1,5,7),(2,4,7).(1,5,7),(2,4,7). A middle value 33 or 55 would now identify the triple, so Stacy’s statement forces the middle value 4.4. Thus C is correct.
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