1995 AMC 12 Problem 1

Attempt Problem 1 of the 1995 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1995 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

Kim earned scores of

87,

83

and

88

on her first three mathematics examinations. If Kim receives a score of

90

on the fourth exam, then her average will

remain the same

increase by

1

increase by

2

increase by

3

increase by

4

Compare

90

with the average of the first three scores

Find the old and new totals before dividing by the number of exams

The first three scores total

87+83+88=258,

so their average is

\frac{258}{3}=86.

With the fourth score, the total is

348,

and the new average is

\frac{348}{4}=87.

It increases by

1,

so the correct answer is B.

Problem 1 in other years