1994 AMC 12 Problem 18

Attempt Problem 18 of the 1994 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1994 AMC 12 solutions, or check the answer key.

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18.

Triangle ABCABC is inscribed in a circle, and ∠B=∠C=4∠A.\angle B=\angle C=4\angle A. If BB and CC are adjacent vertices of a regular polygon of nn sides inscribed in this circle, then n=n=
55
77
99
1515
1818
Answer: C
Concepts:inscribed anglesregular polygons
Small hint:
Use the triangle angle sum to find ∠A\angle A
Big hint:
The central angle subtending BC‾\overline{BC} is twice ∠A\angle A
Solution:
The angle sum gives 9∠A=180∘,9\angle A=180^\circ, so ∠A=20∘.\angle A=20^\circ. The central angle subtending chord BC‾\overline{BC} is therefore 40∘.40^\circ. Adjacent vertices of a regular nn-gon subtend 360∘n,\frac{360^\circ}{n}, so 360∘n=40∘, \frac{360^\circ}{n}=40^\circ, and n=9.n=9. Thus the correct answer is C.
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