1994 AMC 12 Problem 10

Attempt Problem 10 of the 1994 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1994 AMC 12 solutions, or check the answer key.

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10.

For distinct real numbers xx and y,y, let M(x,y)M(x,y) be the larger of xx and yy and let m(x,y)m(x,y) be the smaller of xx and y.y. If a<b<c<d<e, a\lt b\lt c\lt d\lt e, then M(M(a,m(b,c)),m(d,m(a,e)))= \begin{aligned} &M\bigl(M(a,m(b,c)),\\ &\qquad m(d,m(a,e))\bigr)= \end{aligned}
aa
bb
cc
dd
ee
Answer: B
Concepts:nested minimum and maximuminequalities
Small hint:
Evaluate the innermost mm expressions first
Big hint:
The two arguments of the outermost MM reduce to bb and aa
Solution:
From the ordering, m(b,c)=b,m(b,c)=b, so M(a,m(b,c))=M(a,b)=b.M(a,m(b,c))=M(a,b)=b. Also m(a,e)=a,m(a,e)=a, hence m(d,m(a,e))=m(d,a)=a.m(d,m(a,e))=m(d,a)=a. The outer expression is therefore M(b,a)=b.M(b,a)=b. Thus the correct answer is B.
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