1990 AMC 12 Problem 9

Attempt Problem 9 of the 1990 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1990 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

9.

Each edge of a cube is colored either red or black. Every face of the cube has at least one black edge. The smallest possible number of black edges is
22
33
44
55
66
Answer: B
Concepts:cubecovering argumentconstruction
Small hint:
Each edge belongs to exactly two faces
Big hint:
For the matching upper bound, choose three mutually nonadjacent edges
Solution:
Each black edge can cover only its two incident faces, so covering all 66 faces requires at least 33 black edges. Choose edges incident to the face-pairs top/front, bottom/left, and back/right. These three edges cover all six faces, so the minimum is 3.3.
Thus the correct answer is B.
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