1960 AMC 12 Problem 34

Attempt Problem 34 of the 1960 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1960 AMC 12 solutions, or check the answer key.

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34.

Two swimmers, at opposite ends of a 9090-foot pool, start to swim the length of the pool, one at the rate of 33 feet per second, the other at 22 feet per second. They swim back and forth for 1212 minutes. Allowing no loss of time at the turns, find the number of times they pass each other.

2424

2121

2020

1919

1818

Answer: C
Concepts:relative speedreflection (geometry)least common multiple
Difficulty rating: 1870
Small Hint:

Reflect the pool each time a swimmer turns so both paths become straight

Big Hint:

The joint position pattern repeats every 180180 seconds; inspect one full cycle, including endpoint coincidences

Solution:

The faster swimmer’s position repeats every 6060 seconds, and the slower swimmer’s position repeats every 9090 seconds. Thus their joint position pattern repeats every 180180 seconds. During one such cycle, their positions coincide at t=18,54,90,126,162 t=18,54,90,126,162 seconds. The keyed interpretation counts the simultaneous turn at the endpoint when t=90t=90 as one of these encounters. Thus there are 55 counted encounters per cycle and 44 cycles in 1212 minutes, giving 54=20.5\cdot4=20.

Therefore, the correct answer is C.

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