1956 AMC 12 Problem 45

Attempt Problem 45 of the 1956 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1956 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

45.

A wheel with a rubber tire has an outside diameter of 2525 in. When the radius has been decreased a quarter of an inch, the number of revolutions in one mile will:

be increased about 2%2\%

be increased about 1%1\%

be increased about 20%20\%

be increased 12%\dfrac12\%

remain the same

Answer: A
Concepts:circumferenceinverse proportionpercent change
Difficulty rating: 1550
Small Hint:

For a fixed distance, the revolution count is inversely proportional to the wheel’s radius

Big Hint:

Compare the original radius 12.512.5 with the new radius 12.2512.25

Solution:

The original radius is 12.512.5 inches and the new radius is 12.2512.25 inches. For a fixed distance, the number of revolutions varies inversely with radius, so the relative increase is 12.512.251=50491=1492.04%. \begin{aligned} \frac{12.5}{12.25}-1 &=\frac{50}{49}-1\\ &=\frac1{49}\\ &\approx2.04\%. \end{aligned} This is about 2%.2\%.

Thus, the correct answer is A.

← Problem 44#44
Full Exam

Problem 45 in Other Years

1950 AMC 12 · 1951 AMC 12 · 1952 AMC 12 · 1953 AMC 12 · 1954 AMC 12 · 1955 AMC 12 · 1957 AMC 12 · 1958 AMC 12 · 1959 AMC 12