1951 AMC 12 Problem 45

Attempt Problem 45 of the 1951 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1951 AMC 12 solutions, or check the answer key.

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45.

If you are given log8=0.9031\log 8=0.9031 and log9=0.9542,\log 9=0.9542, then the only logarithm that cannot be found without the use of tables is:

log17\log 17

log(54)\log(\frac{5}{4})

log15\log 15

log600\log 600

log0.4\log 0.4

Answer: A
Concepts:logarithmprime factorization
Difficulty rating: 1470
Small Hint:

The two given values determine log2\log2 and log3\log3

Big Hint:

Use log5=1log2\log5=1-\log2, then see which choice has a prime factor other than 2,3,52,3,5

Solution:

From the data, log2=13log8,log3=12log9, \begin{gathered} \log2=\frac13\log8,\\ \log3=\frac12\log9, \end{gathered} and log5=1log2.\log5=1-\log2. Therefore logarithms of products and quotients of powers of 2,3,52,3,5 can be computed. The number 1717 has none of those prime factors, so its logarithm is not determined by the data.

Thus, the correct answer is A.

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Problem 45 in Other Years

1950 AMC 12 · 1952 AMC 12 · 1953 AMC 12 · 1954 AMC 12 · 1955 AMC 12 · 1956 AMC 12 · 1957 AMC 12 · 1958 AMC 12 · 1959 AMC 12