1950 AMC 12 Problem 45

Attempt Problem 45 of the 1950 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1950 AMC 12 solutions, or check the answer key.

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45.

The number of diagonals that can be drawn in a polygon of 100100 sides is:

48504850

49504950

99009900

9898

88008800

Answer: A
Concepts:diagonalcombinations
Difficulty rating: 1410
Small Hint:

Every pair of vertices determines a segment

Big Hint:

Subtract the 100100 sides from the (1002)\binom{100}{2} vertex pairs

Solution:

There are (1002)\binom{100}{2} segments joining pairs of vertices. Exactly 100100 of these are sides, so the number of diagonals is (1002)100=4950100=4850. \begin{aligned} \binom{100}{2}-100 &=4950-100\\ &=4850. \end{aligned}

Thus, the correct answer is A.

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Problem 45 in Other Years

1951 AMC 12 · 1952 AMC 12 · 1953 AMC 12 · 1954 AMC 12 · 1955 AMC 12 · 1956 AMC 12 · 1957 AMC 12 · 1958 AMC 12 · 1959 AMC 12