2025 AMC 10A Problem 22

Attempt Problem 22 of the 2025 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2025 AMC 10A solutions, or check the answer key.

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22.

A circle of radius rr is surrounded by three circles, whose radii are 1,2,1, 2, and 3,3, all externally tangent to the inner circle and externally tangent to each other, as shown in the diagram below.

What is r?r?

14\dfrac{1}{4}

623\dfrac{6}{23}

311\dfrac{3}{11}

517\dfrac{5}{17}

310\dfrac{3}{10}

Answer: B
Concepts:tangent circlescoordinate geometry
Difficulty rating: 2120
Solution:

The three outer centers A,B,CA, B, C are pairwise AB=1+2=3,AB = 1 + 2 = 3, AC=1+3=4,AC = 1 + 3 = 4, and BC=2+3=5BC = 2 + 3 = 5 apart, a 33-44-55 right triangle. Now apply Descartes' Circle Theorem with curvatures 1,12,13,1, \tfrac12, \tfrac13, and 1r,\tfrac1r, all mutually tangent: 1r=1+12+13\frac1r = 1 + \tfrac12 + \tfrac13 +212+16+13+ 2\sqrt{\tfrac12 + \tfrac16 + \tfrac13} =116+21= \tfrac{11}{6} + 2\sqrt{1} =236.= \tfrac{23}{6}. Inverting, r=623.r = \tfrac{6}{23}. Therefore, the answer is B.

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