2024 AMC 10B Problem 22

Below is the professionally curated solution for Problem 22 of the 2024 AMC 10B, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2024 AMC 10B solutions, or check the answer key.

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Concepts:combinationsLegendre’s Formulaprime factorization

Difficulty rating: 2120

22.

A group of 1616 people will be partitioned into 44 indistinguishable 44-person committees. Each committee will have one chairperson and one secretary. The number of different ways to make these assignments can be written as 3rM,3^r M, where rr and MM are positive integers and MM is not divisible by 3.3. What is r?r?

55

66

77

88

99

Solution:

Split 1616 people into 44 indistinguishable groups of 44 in 16!(4!)44!\dfrac{16!}{(4!)^4 \, 4!} ways, then each committee picks a chairperson and a secretary in 43=124 \cdot 3 = 12 ways, a factor of 124.12^4. Now count factors of 3.3. In 16!16! there are 16/3+16/9=6;\lfloor 16/3 \rfloor + \lfloor 16/9 \rfloor = 6; the denominator (4!)44!(4!)^4 \, 4! contributes 41+1=5;4 \cdot 1 + 1 = 5; and 12412^4 contributes 4.4. The exponent is 65+4=5,6 - 5 + 4 = 5, so r=5.r = 5. Therefore, the answer is A.

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