2003 AMC 10B Problem 22

Below is the professionally curated solution for Problem 22 of the 2003 AMC 10B, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2003 AMC 10B solutions, or check the answer key.

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Concepts:date and timesummationprocess simulation

Difficulty rating: 1690

22.

A clock chimes once at 3030 minutes past each hour and chimes on the hour according to the hour. For example, at 1 PM there is one chime and at noon and midnight there are twelve chimes. Starting at 11:15 AM on February 26, 2003, on what date will the 2003rd chime occur?

March 8

March 9

March 10

March 20

March 21

Solution:

Each 1212-hour period has 12+78=9012 + 78 = 90 chimes, so each full day has 180.180.

After 11:15 AM on February 26, the rest of that day has 9191 chimes. Adding 180180 for each following full day, the count reaches 18911891 by the end of March 8.

The remaining chimes fall on March 9: the 2003rd chime is the 112112th chime of that day, occurring at 3:30 PM on March 9.

Thus, the correct answer is B.

Problem 22 in Other Years