2023 AMC 10B Problem 6

Attempt Problem 6 of the 2023 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2023 AMC 10B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

6.

Let L1=1,L_1 = 1, L2=3,L_2 = 3, and Ln+2=Ln+1+LnL_{n+2} = L_{n+1} + L_n for n≥1.n \ge 1. How many terms in the sequence L1,L_1, L2,L_2, L3,L_3, …,\ldots, L2023L_{2023} are even?
673673
10111011
675675
10101010
674674
Answer: E
Concepts:parityrecursionpattern recognition
Small hint:
Track only the parity of the terms: odd, odd, even, and then it repeats
Big hint:
Even terms occur exactly at positions that are multiples of 33
Solution:
Track the parities: 1,3,4,7,11,18,…1, 3, 4, 7, 11, 18, \ldots run odd, odd, even, then repeat with period 3.3. So LnL_n is even exactly when nn is divisible by 3.3. Among 1≤n≤2023,1 \le n \le 2023, that’s ⌊20233⌋=674\lfloor \frac{2023}{3} \rfloor = 674 multiples of 3.3. Therefore, the answer is E.
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