2023 AMC 10A Problem 5

Attempt Problem 5 of the 2023 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2023 AMC 10A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

5.

How many digits are in the base-ten representation of 85⋅510⋅155?8^5 \cdot 5^{10} \cdot 15^5?
1414
1515
1616
1717
1818
Answer: E
Concepts:prime factorizationdigits
Small hint:
Factor each base into primes: 8=238 = 2^3 and 15=3⋅515 = 3 \cdot 5
Big hint:
Combine into 1015⋅35,10^{15} \cdot 3^5, which is 353^5 followed by 1515 zeros
Solution:
Factor everything into primes. 85⋅510⋅1558^5 \cdot 5^{10} \cdot 15^5 =215⋅510⋅35⋅55= 2^{15} \cdot 5^{10} \cdot 3^5 \cdot 5^5 =215⋅515⋅35= 2^{15} \cdot 5^{15} \cdot 3^5 =1015⋅243.= 10^{15} \cdot 243. That’s 243243 followed by 1515 zeros, so it has 3+15=183 + 15 = 18 digits. Thus, E is the correct answer.
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