2007 AMC 10A Problem 5

Below is the professionally curated solution for Problem 5 of the 2007 AMC 10A, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2007 AMC 10A solutions, or check the answer key.

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Concepts:system of equations money

Difficulty rating: 1020

A school store sells $7$ pencils and $8$ notebooks for $\$4.15.$ It also sells $5$ pencils and $3$ notebooks for $\$1.77.$ How much do $16$ pencils and $10$ notebooks cost?

$\$4.76$

$\$5.84$

$\$6.00$

$\$6.16$

$\$6.32$

Solution:

Let $p$ and $n$ be the prices in cents of a pencil and a notebook. Then $7p + 8n = 415$ $5p + 3n = 177.$

Solving this system gives $p = 9$ and $n = 44.$

So $16$ pencils and $10$ notebooks cost $16(9) + 10(44) = 584$ cents, or $\$5.84.$

Thus, the correct answer is B.

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