2000 AMC 10 Problem 5

Below is the professionally curated solution for Problem 5 of the 2000 AMC 10, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2000 AMC 10 solutions, or check the answer key.

All of the real AMC 8, AMC 10, AMC 12, and AIME problems in our complete solution collection are used with official legal permission of the Mathematical Association of America (MAA).

Concepts:triangle areamidpointparallel lines

Difficulty rating: 1240

5.

Points MM and NN are the midpoints of sides PAPA and PBPB of PAB.\triangle PAB. As PP moves along a line that is parallel to side AB,AB, how many of the four quantities listed below change?

(a) the length of the segment MN;MN; (b) the perimeter of PAB;\triangle PAB; (c) the area of PAB;\triangle PAB; (d) the area of trapezoid ABNM.ABNM.

00

11

22

33

44

Solution:

Since MNMN is a midsegment, MN=12AB,MN = \tfrac12 AB, which is fixed.

The base ABAB and the height from PP to ABAB are both constant as PP slides along the parallel line, so the area of PAB\triangle PAB does not change. The trapezoid ABNMABNM is the triangle minus PMN,\triangle PMN, both of whose areas are constant, so its area does not change either.

Only the perimeter changes, since PAPA and PBPB vary as PP moves. So exactly one quantity changes.

Thus, the correct answer is B.

Problem 5 in Other Years