2022 AMC 10B Problem 5

Attempt Problem 5 of the 2022 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2022 AMC 10B solutions, or check the answer key.

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5.

What is the value of (1+13)(1+15)(1+17)(1132)(1152)(1172)?\frac{\left(1+\frac{1}{3}\right)\left(1+\frac15\right)\left(1+\frac17\right)}{\sqrt{\left(1-\frac{1}{3^2}\right)\left(1-\frac{1}{5^2}\right)\left(1-\frac{1}{7^2}\right)}}?

3 \sqrt3

2 2

15 \sqrt{15}

4 4

105 \sqrt{105}

Answer: B
Concepts:difference of squaresradical
Difficulty rating: 1280
Solution:

Let the given positive expression be E.E. Squaring it and using 11/p2=(11/p)(1+1/p)1-1/p^2=(1-1/p)(1+1/p) gives E2=p{3,5,7}1+1/p11/p=426486=4. \begin{aligned} E^2&=\prod_{p\in\{3,5,7\}}\frac{1+1/p}{1-1/p}\\ &=\frac42\cdot\frac64\cdot\frac86=4. \end{aligned} Hence E=2.E=2.

Thus, the answer is B .

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