2021 AMC 10B Fall Problem 16

Attempt Problem 16 of the 2021 AMC 10B Fall below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2021 AMC 10B Fall solutions, or check the answer key.

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16.

Five balls are arranged around a circle. Chris chooses two adjacent balls at random and interchanges them. Then Silva does the same, with her choice of adjacent balls to interchange being independent of Chris's. What is the expected number of balls that occupy their original positions after these two successive transpositions?

1.6 1.6

1.8 1.8

2.0 2.0

2.2 2.2

2.4 2.4

Answer: D
Concepts:expected valuecasework
Difficulty rating: 1420
Solution:

After Chris chooses an adjacent pair, Silva has 55 equally likely adjacent pairs to choose.

If Silva chooses the same pair, all 55 balls return to their original positions. This has probability 15.\frac15.

If Silva chooses a pair sharing exactly one ball with Chris's pair, then 22 balls are in their original positions. There are 22 such pairs, so this has probability 25.\frac25.

If Silva chooses a disjoint adjacent pair, then 11 ball is in its original position. This also has probability 25.\frac25.

The expected number is 515+225+125=115=2.2. \begin{aligned} 5\cdot\frac15+2\cdot\frac25+1\cdot\frac25&=\frac{11}{5}\\ &=2.2. \end{aligned}

Thus, the answer is D .

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