2024 AMC 10A Problem 16

Below is the professionally curated solution for Problem 16 of the 2024 AMC 10A, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2024 AMC 10A solutions, or check the answer key.

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Concepts:similarityarea ratiorectangle

Difficulty rating: 1730

16.

All of the rectangles in the figure below, which is drawn to scale, are similar to the enclosing rectangle. Each number represents the area of the rectangle. What is length AB?AB?

4+454 + 4\sqrt5

10210\sqrt2

5+555 + 5\sqrt5

108410\sqrt[4]{8}

2020

Solution:

Every piece is similar to the whole rectangle, so they all share one aspect ratio. The areas 1,2,4,8,161, 2, 4, 8, 16 (and 9,189, 18) come in factor-of-22 steps, and cutting a rectangle of aspect ratio 2\sqrt2 across its long side gives two similar copies of half the area. That pins the ratio at 2.\sqrt2. The total area is 36+16+8+18+1+9+4+2+32+25+49=200.36 + 16 + 8 + 18 + 1 + 9 + 4 + 2 + 32 + 25 + 49 = 200. The enclosing rectangle satisfies ABAB2=200,AB \cdot \tfrac{AB}{\sqrt2} = 200, so AB2=2002AB^2 = 200\sqrt2 and AB=2002=1084.AB = \sqrt{200\sqrt2} = 10\sqrt[4]{8}. Therefore, the answer is D.

Problem 16 in Other Years