2021 AMC 10A Fall Problem 24

Attempt Problem 24 of the 2021 AMC 10A Fall below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2021 AMC 10A Fall solutions, or check the answer key.

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24.

Each of the 1212 edges of a cube is labeled 00 or 1.1. Two labelings are considered different even if one can be obtained from the other by a sequence of one or more rotations and/or reflections. For how many such labelings is the sum of the labels on the edges of each of the 66 faces of the cube equal to 2?2?

88

1010

1212

1616

2020

Answer: E
Concepts:arrangements with restrictionscube geometrycasework
Difficulty rating: 2390
Solution:

Label one face ABCD.ABCD. Each face must contain two 00s and two 11s, so first split by the pattern on the four edges of ABCD.ABCD.

Case 1: opposite edges of ABCDABCD have the same label. There are 22 such patterns on ABCD.ABCD. For either pattern, once the label of one vertical edge, say AE,AE, is chosen, the face-sum conditions force all remaining labels. This gives 22=42\cdot2=4 labelings.

Case 2: opposite edges of ABCDABCD have different labels. There are 44 such patterns on ABCD.ABCD. For each, the labels of two adjacent vertical edges may be chosen in 44 ways, and then the remaining labels are forced by the face-sum conditions. This gives 44=164\cdot4=16 labelings.

The total is 4+16=20.4+16=20.

Thus, E is the correct answer.

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