2021 AMC 10A Fall Problem 12

Attempt Problem 12 of the 2021 AMC 10A Fall below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2021 AMC 10A Fall solutions, or check the answer key.

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12.

The base-nine representation of the number NN is 27,006,000,0529.27{,}006{,}000{,}052_9. What is the remainder when NN is divided by 5?5?
00
11
22
33
44
Answer: D
Concepts:number basemodular arithmetic
Small hint:
Work modulo 5,5, where 9≡−19\equiv -1
Big hint:
Only the nonzero base-nine digits contribute
Solution:
Note that 9≡−1(mod5). 9 \equiv -1 \pmod{5}. Then if expand NN using the definition of bases, we get N=2⋅910+7⋅99+6⋅96+ N = 2 \cdot 9^{10} + 7 \cdot 9^9 + 6 \cdot 9^6 +5⋅9+2 5 \cdot 9 + 2 ≡2(−1)10+7(−1)9+6(−1)6+ \equiv 2 (-1)^{10} + 7 (-1)^9 + 6 (-1)^6 +5(−1)+2(mod5) 5 (-1) + 2 \pmod{5} ≡2−7+6−5+2(mod5) \equiv 2 - 7 + 6 - 5 + 2 \pmod{5} ≡3(mod5). \equiv 3 \pmod{5}.
Thus, D is the correct answer.
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