2010 AMC 10A Problem 12

Below is the professionally curated solution for Problem 12 of the 2010 AMC 10A, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2010 AMC 10A solutions, or check the answer key.

All of the real AMC 8, AMC 10, AMC 12, and AIME problems in our complete solution collection are used with official legal permission of the Mathematical Association of America (MAA).

Concepts:power scaling of length, area, and volumeratio and proportion

Difficulty rating: 1420

12.

Logan is constructing a scaled model of his town. The city's water tower stands 4040 meters high, and the top portion is a sphere that holds 100,000100,000 liters of water. Logan's miniature water tower holds 0.10.1 liters. How tall, in meters, should Logan make his tower?

0.040.04

0.4π\dfrac{0.4}{\pi}

0.40.4

4π\dfrac{4}{\pi}

44

Solution:

The miniature tower holds 100,000.1=1,000,000 \dfrac{100,000}{.1} = 1,000,000 times less water than the actual tower. Since this is the ratio for volumes, the ratio of heights is (1,000,000)1/3=100. (1,000,000)^{1 / 3} = 100. This means that the height of the miniature tower is 40100=.4. \dfrac{40}{100} = .4.

Thus, C is the correct answer.

Problem 12 in Other Years