2018 AMC 10B Problem 14

Attempt Problem 14 of the 2018 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2018 AMC 10B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

14.

A list of 20182018 positive integers has a unique mode, which occurs exactly 1010 times. What is the least number of distinct values that can occur in the list?
202202
223223
224224
225225
234234
Answer: D
Concepts:modeoptimization
Small hint:
Every value other than the mode can appear at most 99 times, to keep the mode unique
Big hint:
With dd distinct values the list holds at most 10+9(d−1)10 + 9(d-1) entries; make this at least 20182018
Solution:
The mode shows up 1010 times. To keep the number of distinct values small, let every other value repeat as much as the rules allow, which is 99 times each (any more would tie the mode). With dd distinct values the list holds at most 10+9(d−1)10 + 9(d-1) entries. We need 10+9(d−1)≥2018,10 + 9(d-1) \ge 2018, so d−1≥223.1,d - 1 \ge 223.1, giving d≥225.d \ge 225. Therefore, the answer is D.
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