2018 AMC 10A Problem 10

Attempt Problem 10 of the 2018 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2018 AMC 10A solutions, or check the answer key.

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10.

Suppose that real number xx satisfies 49x225x2=3.\sqrt{49-x^2}-\sqrt{25-x^2}=3. What is the value of 49x2+25x2?\sqrt{49-x^2}+\sqrt{25-x^2}?

88

33+8\sqrt{33}+8

99

210+42\sqrt{10}+4

1212

Answer: A
Concepts:radicaldifference of squaresalgebraic manipulation
Difficulty rating: 1310
Solution:

Note that the left hand side of the equation and the desired expression are conjugates. Multiplying them would remove the square roots.

Multiplying them yields 49x225+x2=24. 49 - x^2 - 25 + x^2 = 24.

This means that the product of the values of the expressions is equal to 24.24. The desired value is therefore 24÷3=8.24 \div 3 = 8.

Thus, A is the correct answer.

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