2017 AMC 10A Problem 8

Attempt Problem 8 of the 2017 AMC 10A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2017 AMC 10A solutions, or check the answer key.

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8.

At a gathering of 3030 people, there are 2020 people who all know each other and 1010 people who know no one. People who know each other hug, and people who do not know each other shake hands. How many handshakes occur?

240240

245245

290290

480480

490490

Answer: B
Concepts:counting pairscombinations
Difficulty rating: 1020
Solution:

Each of the 1010 people shake hands with each of the 2020 people. This results in 1020=20010 \cdot 20 = 200 handshakes.

There are also (102)=45\binom{10}{2} = 45 handshakes within the 1010 people (every pair of people shake hands).

Therefore, the total number of handshakes is 200+45=245.200 + 45 = 245.

Thus, B is the correct answer.

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