2014 AMC 10B Problem 12

Attempt Problem 12 of the 2014 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2014 AMC 10B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

12.

The largest divisor of 2,014,000,0002{,}014{,}000{,}000 is itself. What is its fifth-largest divisor?
125,875,000125{,}875{,}000
201,400,000201{,}400{,}000
251,750,000251{,}750{,}000
402,800,000402{,}800{,}000
503,500,000503{,}500{,}000
Answer: C
Concepts:factorprime factorization
Small hint:
The fifth largest divisor pairs with the fifth smallest divisor
Big hint:
List the smallest divisors from the prime factorization
Solution:
The fifth-largest divisor is 2,014,000,0002,014,000,000 divided by the fifth smallest divisor.
The prime factorization of 2,014,000,0002,014,000,000 is: 27⋅56⋅19⋅53.2^7\cdot 5^6 \cdot 19\cdot 53. This makes the first 55 smallest divisors 1,2,4,5,8.1,2,4,5,8. Therefore, the fifth smallest divisor is 8,8, and the fifth largest divisor must be: 20140000008=251750000.\dfrac{2014000000}8 =251750000.
Thus, the correct answer is C .
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