2014 AMC 10B Problem 10

Attempt Problem 10 of the 2014 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2014 AMC 10B solutions, or check the answer key.

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10.

In the addition shown below A,A, B,B, C,C, and DD are distinct digits. How many different values are possible for D?D? ABBCB+ BCADADBDDD\begin{array}{r} ABBCB \\ + \ BCADA \\ \hline DBDDD \end{array}

2 2

4 4

7 7

8 8

9 9

Answer: C
Concepts:cryptarithmdigitscasework
Difficulty rating: 1370
Solution:

From the leftmost column, there is no carry into a sixth digit, so A+B=D9A+B=D\le 9.

The units column is B+A=DB+A=D, so it also has no carry. The tens column then gives C+D=DC+D=D, hence C=0C=0.

Since AA and BB are distinct nonzero digits, D=A+BD=A+B can be any digit from 33 through 99. For example, (A,B)=(1,2),(A,B)=(1,2), (1,3),(1,3), (2,3),(2,3), (2,4),(2,4), (2,5),(2,5), (2,6),(2,6), (2,7)(2,7) give D=3,4,5,6,7,8,9D=3,4,5,6,7,8,9.

Thus there are 77 possible values of DD, and the correct answer is C .

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