2013 AMC 10B Problem 6

Attempt Problem 6 of the 2013 AMC 10B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2013 AMC 10B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

6.

The average age of 3333 fifth-graders is 11.11. The average age of 5555 of their parents is 33.33. What is the average age of all of these parents and fifth-graders?
22 22
23.25 23.25
24.75 24.75
26.25 26.25
28 28
Answer: C
Concepts:mean
Small hint:
Use total age, not the average of the two averages
Big hint:
Compute 33⋅11+55⋅3333\cdot11+55\cdot33 and divide by 8888
Solution:
The sum of the ages of all the fifth-graders and their parents is: 33⋅11+55⋅33=66⋅33.33\cdot 11+55\cdot 33 = 66\cdot 33.
Then, as the average is the sum divided by the number of people, the average age must be: 66⋅3388=34⋅33=24.75.\dfrac{66\cdot 33}{88} = \dfrac 34 \cdot 33 = 24.75 .
Thus, the correct answer is C .
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